3.1188 \(\int \frac{\cos (c+d x) \cot ^3(c+d x)}{(a+b \sin (c+d x))^{5/2}} \, dx\)

Optimal. Leaf size=407 \[ -\frac{\left (8 a^2-105 b^2\right ) \cos (c+d x)}{12 a^4 d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-35 b^2\right ) \cot (c+d x)}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}+\frac{\left (4 a^2-7 b^2\right ) \cot (c+d x)}{6 a^2 b d (a+b \sin (c+d x))^{3/2}}+\frac{\left (8 a^2-35 b^2\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-105 b^2\right ) \sqrt{a+b \sin (c+d x)} E\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{12 a^4 b d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}-\frac{\left (12 a^2-35 b^2\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} \Pi \left (2;\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{4 a^4 d \sqrt{a+b \sin (c+d x)}}-\frac{\cot (c+d x) \csc (c+d x)}{2 a d (a+b \sin (c+d x))^{3/2}} \]

[Out]

((4*a^2 - 7*b^2)*Cot[c + d*x])/(6*a^2*b*d*(a + b*Sin[c + d*x])^(3/2)) - (Cot[c + d*x]*Csc[c + d*x])/(2*a*d*(a
+ b*Sin[c + d*x])^(3/2)) - ((8*a^2 - 105*b^2)*Cos[c + d*x])/(12*a^4*d*Sqrt[a + b*Sin[c + d*x]]) - ((8*a^2 - 35
*b^2)*Cot[c + d*x])/(12*a^3*b*d*Sqrt[a + b*Sin[c + d*x]]) - ((8*a^2 - 105*b^2)*EllipticE[(c - Pi/2 + d*x)/2, (
2*b)/(a + b)]*Sqrt[a + b*Sin[c + d*x]])/(12*a^4*b*d*Sqrt[(a + b*Sin[c + d*x])/(a + b)]) + ((8*a^2 - 35*b^2)*El
lipticF[(c - Pi/2 + d*x)/2, (2*b)/(a + b)]*Sqrt[(a + b*Sin[c + d*x])/(a + b)])/(12*a^3*b*d*Sqrt[a + b*Sin[c +
d*x]]) - ((12*a^2 - 35*b^2)*EllipticPi[2, (c - Pi/2 + d*x)/2, (2*b)/(a + b)]*Sqrt[(a + b*Sin[c + d*x])/(a + b)
])/(4*a^4*d*Sqrt[a + b*Sin[c + d*x]])

________________________________________________________________________________________

Rubi [A]  time = 1.26521, antiderivative size = 407, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 10, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.345, Rules used = {2890, 3055, 3059, 2655, 2653, 3002, 2663, 2661, 2807, 2805} \[ -\frac{\left (8 a^2-105 b^2\right ) \cos (c+d x)}{12 a^4 d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-35 b^2\right ) \cot (c+d x)}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}+\frac{\left (4 a^2-7 b^2\right ) \cot (c+d x)}{6 a^2 b d (a+b \sin (c+d x))^{3/2}}+\frac{\left (8 a^2-35 b^2\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-105 b^2\right ) \sqrt{a+b \sin (c+d x)} E\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{12 a^4 b d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}-\frac{\left (12 a^2-35 b^2\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} \Pi \left (2;\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{4 a^4 d \sqrt{a+b \sin (c+d x)}}-\frac{\cot (c+d x) \csc (c+d x)}{2 a d (a+b \sin (c+d x))^{3/2}} \]

Antiderivative was successfully verified.

[In]

Int[(Cos[c + d*x]*Cot[c + d*x]^3)/(a + b*Sin[c + d*x])^(5/2),x]

[Out]

((4*a^2 - 7*b^2)*Cot[c + d*x])/(6*a^2*b*d*(a + b*Sin[c + d*x])^(3/2)) - (Cot[c + d*x]*Csc[c + d*x])/(2*a*d*(a
+ b*Sin[c + d*x])^(3/2)) - ((8*a^2 - 105*b^2)*Cos[c + d*x])/(12*a^4*d*Sqrt[a + b*Sin[c + d*x]]) - ((8*a^2 - 35
*b^2)*Cot[c + d*x])/(12*a^3*b*d*Sqrt[a + b*Sin[c + d*x]]) - ((8*a^2 - 105*b^2)*EllipticE[(c - Pi/2 + d*x)/2, (
2*b)/(a + b)]*Sqrt[a + b*Sin[c + d*x]])/(12*a^4*b*d*Sqrt[(a + b*Sin[c + d*x])/(a + b)]) + ((8*a^2 - 35*b^2)*El
lipticF[(c - Pi/2 + d*x)/2, (2*b)/(a + b)]*Sqrt[(a + b*Sin[c + d*x])/(a + b)])/(12*a^3*b*d*Sqrt[a + b*Sin[c +
d*x]]) - ((12*a^2 - 35*b^2)*EllipticPi[2, (c - Pi/2 + d*x)/2, (2*b)/(a + b)]*Sqrt[(a + b*Sin[c + d*x])/(a + b)
])/(4*a^4*d*Sqrt[a + b*Sin[c + d*x]])

Rule 2890

Int[cos[(e_.) + (f_.)*(x_)]^4*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)
, x_Symbol] :> Simp[(Cos[e + f*x]*(d*Sin[e + f*x])^(n + 1)*(a + b*Sin[e + f*x])^(m + 1))/(a*d*f*(n + 1)), x] +
 (Dist[1/(a^2*b*d*(n + 1)*(m + 1)), Int[(d*Sin[e + f*x])^(n + 1)*(a + b*Sin[e + f*x])^(m + 1)*Simp[a^2*(n + 1)
*(n + 2) - b^2*(m + n + 2)*(m + n + 3) + a*b*(m + 1)*Sin[e + f*x] - (a^2*(n + 1)*(n + 3) - b^2*(m + n + 2)*(m
+ n + 4))*Sin[e + f*x]^2, x], x], x] - Simp[((a^2*(n + 1) - b^2*(m + n + 2))*Cos[e + f*x]*(d*Sin[e + f*x])^(n
+ 2)*(a + b*Sin[e + f*x])^(m + 1))/(a^2*b*d^2*f*(n + 1)*(m + 1)), x]) /; FreeQ[{a, b, d, e, f}, x] && NeQ[a^2
- b^2, 0] && IntegersQ[2*m, 2*n] && LtQ[m, -1] && LtQ[n, -1]

Rule 3055

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*s
in[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> -Simp[((A*b^2 - a*b*B + a^2*C)*Cos[e +
 f*x]*(a + b*Sin[e + f*x])^(m + 1)*(c + d*Sin[e + f*x])^(n + 1))/(f*(m + 1)*(b*c - a*d)*(a^2 - b^2)), x] + Dis
t[1/((m + 1)*(b*c - a*d)*(a^2 - b^2)), Int[(a + b*Sin[e + f*x])^(m + 1)*(c + d*Sin[e + f*x])^n*Simp[(m + 1)*(b
*c - a*d)*(a*A - b*B + a*C) + d*(A*b^2 - a*b*B + a^2*C)*(m + n + 2) - (c*(A*b^2 - a*b*B + a^2*C) + (m + 1)*(b*
c - a*d)*(A*b - a*B + b*C))*Sin[e + f*x] - d*(A*b^2 - a*b*B + a^2*C)*(m + n + 3)*Sin[e + f*x]^2, x], x], x] /;
 FreeQ[{a, b, c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && Lt
Q[m, -1] && ((EqQ[a, 0] && IntegerQ[m] &&  !IntegerQ[n]) ||  !(IntegerQ[2*n] && LtQ[n, -1] && ((IntegerQ[n] &&
  !IntegerQ[m]) || EqQ[a, 0])))

Rule 3059

Int[((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2)/(Sqrt[(a_.) + (b_.)*sin[(e_.) +
(f_.)*(x_)]]*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])), x_Symbol] :> Dist[C/(b*d), Int[Sqrt[a + b*Sin[e + f*x]]
, x], x] - Dist[1/(b*d), Int[Simp[a*c*C - A*b*d + (b*c*C - b*B*d + a*C*d)*Sin[e + f*x], x]/(Sqrt[a + b*Sin[e +
 f*x]]*(c + d*Sin[e + f*x])), x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2
- b^2, 0] && NeQ[c^2 - d^2, 0]

Rule 2655

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[Sqrt[a + b*Sin[c + d*x]]/Sqrt[(a + b*Sin[c +
 d*x])/(a + b)], Int[Sqrt[a/(a + b) + (b*Sin[c + d*x])/(a + b)], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 -
 b^2, 0] &&  !GtQ[a + b, 0]

Rule 2653

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*Sqrt[a + b]*EllipticE[(1*(c - Pi/2 + d*x)
)/2, (2*b)/(a + b)])/d, x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]

Rule 3002

Int[(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)]))/((c_.) + (d_.)*sin[
(e_.) + (f_.)*(x_)]), x_Symbol] :> Dist[B/d, Int[(a + b*Sin[e + f*x])^m, x], x] - Dist[(B*c - A*d)/d, Int[(a +
 b*Sin[e + f*x])^m/(c + d*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, A, B, m}, x] && NeQ[b*c - a*d, 0]
&& NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0]

Rule 2663

Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[Sqrt[(a + b*Sin[c + d*x])/(a + b)]/Sqrt[a
+ b*Sin[c + d*x]], Int[1/Sqrt[a/(a + b) + (b*Sin[c + d*x])/(a + b)], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a
^2 - b^2, 0] &&  !GtQ[a + b, 0]

Rule 2661

Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticF[(1*(c - Pi/2 + d*x))/2, (2*b)
/(a + b)])/(d*Sqrt[a + b]), x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]

Rule 2807

Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]]), x_Symbol] :> Dist
[Sqrt[(c + d*Sin[e + f*x])/(c + d)]/Sqrt[c + d*Sin[e + f*x]], Int[1/((a + b*Sin[e + f*x])*Sqrt[c/(c + d) + (d*
Sin[e + f*x])/(c + d)]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && N
eQ[c^2 - d^2, 0] &&  !GtQ[c + d, 0]

Rule 2805

Int[1/(((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])*Sqrt[(c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]]), x_Symbol] :> Simp
[(2*EllipticPi[(2*b)/(a + b), (1*(e - Pi/2 + f*x))/2, (2*d)/(c + d)])/(f*(a + b)*Sqrt[c + d]), x] /; FreeQ[{a,
 b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[c + d, 0]

Rubi steps

\begin{align*} \int \frac{\cos (c+d x) \cot ^3(c+d x)}{(a+b \sin (c+d x))^{5/2}} \, dx &=\frac{\left (4 a^2-7 b^2\right ) \cot (c+d x)}{6 a^2 b d (a+b \sin (c+d x))^{3/2}}-\frac{\cot (c+d x) \csc (c+d x)}{2 a d (a+b \sin (c+d x))^{3/2}}+\frac{\int \frac{\csc ^2(c+d x) \left (\frac{1}{4} \left (8 a^2-35 b^2\right )-\frac{3}{2} a b \sin (c+d x)+\frac{21}{4} b^2 \sin ^2(c+d x)\right )}{(a+b \sin (c+d x))^{3/2}} \, dx}{3 a^2 b}\\ &=\frac{\left (4 a^2-7 b^2\right ) \cot (c+d x)}{6 a^2 b d (a+b \sin (c+d x))^{3/2}}-\frac{\cot (c+d x) \csc (c+d x)}{2 a d (a+b \sin (c+d x))^{3/2}}-\frac{\left (8 a^2-35 b^2\right ) \cot (c+d x)}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}+\frac{\int \frac{\csc (c+d x) \left (-\frac{3}{8} b \left (12 a^2-35 b^2\right )+\frac{21}{4} a b^2 \sin (c+d x)+\frac{1}{8} b \left (8 a^2-35 b^2\right ) \sin ^2(c+d x)\right )}{(a+b \sin (c+d x))^{3/2}} \, dx}{3 a^3 b}\\ &=\frac{\left (4 a^2-7 b^2\right ) \cot (c+d x)}{6 a^2 b d (a+b \sin (c+d x))^{3/2}}-\frac{\cot (c+d x) \csc (c+d x)}{2 a d (a+b \sin (c+d x))^{3/2}}-\frac{\left (8 a^2-105 b^2\right ) \cos (c+d x)}{12 a^4 d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-35 b^2\right ) \cot (c+d x)}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}+\frac{2 \int \frac{\csc (c+d x) \left (-\frac{3}{16} b \left (12 a^4-47 a^2 b^2+35 b^4\right )+\frac{35}{8} a b^2 \left (a^2-b^2\right ) \sin (c+d x)-\frac{1}{16} b \left (8 a^4-113 a^2 b^2+105 b^4\right ) \sin ^2(c+d x)\right )}{\sqrt{a+b \sin (c+d x)}} \, dx}{3 a^4 b \left (a^2-b^2\right )}\\ &=\frac{\left (4 a^2-7 b^2\right ) \cot (c+d x)}{6 a^2 b d (a+b \sin (c+d x))^{3/2}}-\frac{\cot (c+d x) \csc (c+d x)}{2 a d (a+b \sin (c+d x))^{3/2}}-\frac{\left (8 a^2-105 b^2\right ) \cos (c+d x)}{12 a^4 d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-35 b^2\right ) \cot (c+d x)}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}-\frac{2 \int \frac{\csc (c+d x) \left (\frac{3}{16} b^2 \left (12 a^4-47 a^2 b^2+35 b^4\right )-\frac{1}{16} a b \left (8 a^4-43 a^2 b^2+35 b^4\right ) \sin (c+d x)\right )}{\sqrt{a+b \sin (c+d x)}} \, dx}{3 a^4 b^2 \left (a^2-b^2\right )}+\frac{\left (-8 a^4+113 a^2 b^2-105 b^4\right ) \int \sqrt{a+b \sin (c+d x)} \, dx}{24 a^4 b \left (a^2-b^2\right )}\\ &=\frac{\left (4 a^2-7 b^2\right ) \cot (c+d x)}{6 a^2 b d (a+b \sin (c+d x))^{3/2}}-\frac{\cot (c+d x) \csc (c+d x)}{2 a d (a+b \sin (c+d x))^{3/2}}-\frac{\left (8 a^2-105 b^2\right ) \cos (c+d x)}{12 a^4 d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-35 b^2\right ) \cot (c+d x)}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}-\frac{\left (12 a^2-35 b^2\right ) \int \frac{\csc (c+d x)}{\sqrt{a+b \sin (c+d x)}} \, dx}{8 a^4}+\frac{\left (8 a^4-43 a^2 b^2+35 b^4\right ) \int \frac{1}{\sqrt{a+b \sin (c+d x)}} \, dx}{24 a^3 b \left (a^2-b^2\right )}+\frac{\left (\left (-8 a^4+113 a^2 b^2-105 b^4\right ) \sqrt{a+b \sin (c+d x)}\right ) \int \sqrt{\frac{a}{a+b}+\frac{b \sin (c+d x)}{a+b}} \, dx}{24 a^4 b \left (a^2-b^2\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}\\ &=\frac{\left (4 a^2-7 b^2\right ) \cot (c+d x)}{6 a^2 b d (a+b \sin (c+d x))^{3/2}}-\frac{\cot (c+d x) \csc (c+d x)}{2 a d (a+b \sin (c+d x))^{3/2}}-\frac{\left (8 a^2-105 b^2\right ) \cos (c+d x)}{12 a^4 d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-35 b^2\right ) \cot (c+d x)}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-105 b^2\right ) E\left (\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )|\frac{2 b}{a+b}\right ) \sqrt{a+b \sin (c+d x)}}{12 a^4 b d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}-\frac{\left (\left (12 a^2-35 b^2\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}\right ) \int \frac{\csc (c+d x)}{\sqrt{\frac{a}{a+b}+\frac{b \sin (c+d x)}{a+b}}} \, dx}{8 a^4 \sqrt{a+b \sin (c+d x)}}+\frac{\left (\left (8 a^4-43 a^2 b^2+35 b^4\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}\right ) \int \frac{1}{\sqrt{\frac{a}{a+b}+\frac{b \sin (c+d x)}{a+b}}} \, dx}{24 a^3 b \left (a^2-b^2\right ) \sqrt{a+b \sin (c+d x)}}\\ &=\frac{\left (4 a^2-7 b^2\right ) \cot (c+d x)}{6 a^2 b d (a+b \sin (c+d x))^{3/2}}-\frac{\cot (c+d x) \csc (c+d x)}{2 a d (a+b \sin (c+d x))^{3/2}}-\frac{\left (8 a^2-105 b^2\right ) \cos (c+d x)}{12 a^4 d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-35 b^2\right ) \cot (c+d x)}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}-\frac{\left (8 a^2-105 b^2\right ) E\left (\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )|\frac{2 b}{a+b}\right ) \sqrt{a+b \sin (c+d x)}}{12 a^4 b d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}+\frac{\left (8 a^2-35 b^2\right ) F\left (\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )|\frac{2 b}{a+b}\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}{12 a^3 b d \sqrt{a+b \sin (c+d x)}}-\frac{\left (12 a^2-35 b^2\right ) \Pi \left (2;\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )|\frac{2 b}{a+b}\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}{4 a^4 d \sqrt{a+b \sin (c+d x)}}\\ \end{align*}

Mathematica [C]  time = 6.6142, size = 622, normalized size = 1.53 \[ \frac{\sqrt{a+b \sin (c+d x)} \left (-\frac{2 \left (a^2 \cos (c+d x)-9 b^2 \cos (c+d x)\right )}{3 a^4 (a+b \sin (c+d x))}-\frac{2 \left (a^2 \cos (c+d x)-b^2 \cos (c+d x)\right )}{3 a^3 (a+b \sin (c+d x))^2}+\frac{11 b \cot (c+d x)}{4 a^4}-\frac{\cot (c+d x) \csc (c+d x)}{2 a^3}\right )}{d}+\frac{-\frac{2 \left (315 b^2-80 a^2\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} \Pi \left (2;\frac{1}{2} \left (-c-d x+\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{\sqrt{a+b \sin (c+d x)}}-\frac{2 i \left (8 a^2-105 b^2\right ) \cos (c+d x) \cos (2 (c+d x)) \sqrt{\frac{b-b \sin (c+d x)}{a+b}} \sqrt{-\frac{b \sin (c+d x)+b}{a-b}} \left (2 a (a-b) E\left (i \sinh ^{-1}\left (\sqrt{-\frac{1}{a+b}} \sqrt{a+b \sin (c+d x)}\right )|\frac{a+b}{a-b}\right )+b \left (2 a F\left (i \sinh ^{-1}\left (\sqrt{-\frac{1}{a+b}} \sqrt{a+b \sin (c+d x)}\right )|\frac{a+b}{a-b}\right )-b \Pi \left (\frac{a+b}{a};i \sinh ^{-1}\left (\sqrt{-\frac{1}{a+b}} \sqrt{a+b \sin (c+d x)}\right )|\frac{a+b}{a-b}\right )\right )\right )}{a \sqrt{-\frac{1}{a+b}} \sqrt{1-\sin ^2(c+d x)} \left (-2 a^2+4 a (a+b \sin (c+d x))-2 (a+b \sin (c+d x))^2+b^2\right ) \sqrt{-\frac{a^2-2 a (a+b \sin (c+d x))+(a+b \sin (c+d x))^2-b^2}{b^2}}}-\frac{280 a b \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{2} \left (-c-d x+\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{\sqrt{a+b \sin (c+d x)}}}{48 a^4 d} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(Cos[c + d*x]*Cot[c + d*x]^3)/(a + b*Sin[c + d*x])^(5/2),x]

[Out]

(Sqrt[a + b*Sin[c + d*x]]*((11*b*Cot[c + d*x])/(4*a^4) - (Cot[c + d*x]*Csc[c + d*x])/(2*a^3) - (2*(a^2*Cos[c +
 d*x] - b^2*Cos[c + d*x]))/(3*a^3*(a + b*Sin[c + d*x])^2) - (2*(a^2*Cos[c + d*x] - 9*b^2*Cos[c + d*x]))/(3*a^4
*(a + b*Sin[c + d*x]))))/d + ((-280*a*b*EllipticF[(-c + Pi/2 - d*x)/2, (2*b)/(a + b)]*Sqrt[(a + b*Sin[c + d*x]
)/(a + b)])/Sqrt[a + b*Sin[c + d*x]] - (2*(-80*a^2 + 315*b^2)*EllipticPi[2, (-c + Pi/2 - d*x)/2, (2*b)/(a + b)
]*Sqrt[(a + b*Sin[c + d*x])/(a + b)])/Sqrt[a + b*Sin[c + d*x]] - ((2*I)*(8*a^2 - 105*b^2)*Cos[c + d*x]*Cos[2*(
c + d*x)]*(2*a*(a - b)*EllipticE[I*ArcSinh[Sqrt[-(a + b)^(-1)]*Sqrt[a + b*Sin[c + d*x]]], (a + b)/(a - b)] + b
*(2*a*EllipticF[I*ArcSinh[Sqrt[-(a + b)^(-1)]*Sqrt[a + b*Sin[c + d*x]]], (a + b)/(a - b)] - b*EllipticPi[(a +
b)/a, I*ArcSinh[Sqrt[-(a + b)^(-1)]*Sqrt[a + b*Sin[c + d*x]]], (a + b)/(a - b)]))*Sqrt[(b - b*Sin[c + d*x])/(a
 + b)]*Sqrt[-((b + b*Sin[c + d*x])/(a - b))])/(a*Sqrt[-(a + b)^(-1)]*Sqrt[1 - Sin[c + d*x]^2]*(-2*a^2 + b^2 +
4*a*(a + b*Sin[c + d*x]) - 2*(a + b*Sin[c + d*x])^2)*Sqrt[-((a^2 - b^2 - 2*a*(a + b*Sin[c + d*x]) + (a + b*Sin
[c + d*x])^2)/b^2)]))/(48*a^4*d)

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Maple [B]  time = 2.039, size = 2617, normalized size = 6.4 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)*cot(d*x+c)^3/(a+b*sin(d*x+c))^(5/2),x)

[Out]

1/12*(105*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*Ellip
ticPi(((a+b*sin(d*x+c))/(a-b))^(1/2),(a-b)/a,((a-b)/(a+b))^(1/2))*a*b^5*sin(d*x+c)^2+78*((a+b*sin(d*x+c))/(a-b
))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1
/2),((a-b)/(a+b))^(1/2))*a^4*b^2*sin(d*x+c)^2+35*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2
)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^3*b^3*sin(d*
x+c)^2-105*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*Elli
pticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^2*b^4*sin(d*x+c)^2-36*((a+b*sin(d*x+c))/(a-b))^(1/
2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticPi(((a+b*sin(d*x+c))/(a-b))^(1/2),(
a-b)/a,((a-b)/(a+b))^(1/2))*a^2*b^4*sin(d*x+c)^3-105*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^
(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticPi(((a+b*sin(d*x+c))/(a-b))^(1/2),(a-b)/a,((a-b)/(a+b))^(1/2))*a
*b^5*sin(d*x+c)^3-113*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))
^(1/2)*EllipticE(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^4*b^2*sin(d*x+c)^2+105*((a+b*sin(d*x+c)
)/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticE(((a+b*sin(d*x+c))/(a-
b))^(1/2),((a-b)/(a+b))^(1/2))*a^2*b^4*sin(d*x+c)^2-8*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))
^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^5*b*sin
(d*x+c)^2+36*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*El
lipticPi(((a+b*sin(d*x+c))/(a-b))^(1/2),(a-b)/a,((a-b)/(a+b))^(1/2))*a^4*b^2*sin(d*x+c)^2-36*((a+b*sin(d*x+c))
/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticPi(((a+b*sin(d*x+c))/(a-
b))^(1/2),(a-b)/a,((a-b)/(a+b))^(1/2))*a^3*b^3*sin(d*x+c)^2-105*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1
)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticPi(((a+b*sin(d*x+c))/(a-b))^(1/2),(a-b)/a,((a-b)/(a+b
))^(1/2))*a^2*b^4*sin(d*x+c)^2+8*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c
))*b/(a-b))^(1/2)*EllipticE(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^5*b*sin(d*x+c)^3-105*a*b^5*s
in(d*x+c)^5-140*a^2*b^4*sin(d*x+c)^4-29*a^3*b^3*sin(d*x+c)^3+105*a*b^5*sin(d*x+c)^3-10*a^4*b^2*sin(d*x+c)^2+14
0*a^2*b^4*sin(d*x+c)^2+21*a^3*b^3*sin(d*x+c)-6*a^4*b^2+105*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(
a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticPi(((a+b*sin(d*x+c))/(a-b))^(1/2),(a-b)/a,((a-b)/(a+b))^(1
/2))*b^6*sin(d*x+c)^3-113*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a
-b))^(1/2)*EllipticE(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^3*b^3*sin(d*x+c)^3+105*((a+b*sin(d*
x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticE(((a+b*sin(d*x+c))
/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a*b^5*sin(d*x+c)^3-8*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b
))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^4*b^2
*sin(d*x+c)^3+78*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2
)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^3*b^3*sin(d*x+c)^3+35*((a+b*sin(d*x+c))/(a-b
))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1
/2),((a-b)/(a+b))^(1/2))*a^2*b^4*sin(d*x+c)^3-105*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/
2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a*b^5*sin(d*x
+c)^3+36*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*Ellipt
icPi(((a+b*sin(d*x+c))/(a-b))^(1/2),(a-b)/a,((a-b)/(a+b))^(1/2))*a^3*b^3*sin(d*x+c)^3+8*a^3*b^3*sin(d*x+c)^5+1
6*a^4*b^2*sin(d*x+c)^4+8*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-
b))^(1/2)*EllipticE(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^6*sin(d*x+c)^2)/a^5/sin(d*x+c)^2/(a+
b*sin(d*x+c))^(3/2)/b^2/cos(d*x+c)/d

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Maxima [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)*cot(d*x+c)^3/(a+b*sin(d*x+c))^(5/2),x, algorithm="maxima")

[Out]

Timed out

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Fricas [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)*cot(d*x+c)^3/(a+b*sin(d*x+c))^(5/2),x, algorithm="fricas")

[Out]

Timed out

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)*cot(d*x+c)**3/(a+b*sin(d*x+c))**(5/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (d x + c\right ) \cot \left (d x + c\right )^{3}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)*cot(d*x+c)^3/(a+b*sin(d*x+c))^(5/2),x, algorithm="giac")

[Out]

integrate(cos(d*x + c)*cot(d*x + c)^3/(b*sin(d*x + c) + a)^(5/2), x)